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Gas particles
are in constant, random motion.
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They collide with each
other and with the walls of the container.
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On
the average, the collisions that occur are elastic.
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Except for collisions,
the gas particles do not interact with each other.
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The pressure that a gas
exerts is caused by the collisions of its molecules with the walls
of the container.
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The force applied on the
walls of the container by the gas particles is equal but opposite
to the force applied on the gas particles by the wall.
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The kinetic energy of the
gas molecules is directly proportional to the
temperature of the gas!

ISOBARIC
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Pressure is constant
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ISOCHORIC or ISOVOLUMETRIC
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Volume is constant
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ISOTHERMAL
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Temperature is constant
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Visualize the Properties of the IDEAL
GAS LAW
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How Does This All Connect?
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The average force exerted
on the kinetic gas molecules by the wall is given by Average
force x (time between succesive collisions)=
(Final momentum - Initial momentum)
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The time for a gas molecule
to travel from one end of the box of length L to hit the wall =(L/v).
That means that F x (L/v) =[+mv - (-mv)] or Fx L =
2mv2.
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Since Newton's Third Law
states that the force applied by the wall to the molecules is equal
but opposite to the force applied by the molecules to the wall then
the average Force applied on the one wall shown above by ONE molecule
= + 2mv2/L.
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For N molecules in the
6 sided box, an average of N/6 are coming toward the box to hit.
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So Total Force x L = [2mv2]
x N/6 =N mv2 /(3) .
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But Force
x L = P x A x L since P= F/A
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That means
that P x A X L = P x V (Volume equals base area x height)
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So P x
V= N
mv2 /(3)
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And Since PV = n RT (from
the Universal Gas Law then nRT = N mv2
/(3)
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Recall that N = n x NA
(Avagadro's Number)
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Going to step 9 and substituting,
n RT = n x NA mv2/(3)
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Using algebra,
mv2=3 [R/NA ]
T
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If we multiply both sides
by 1/2 then [mv2]/2=3/2 [R/NA
] T
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This becomes KE average
= 3/2 kT where k = [R/NA
]
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k = 1.38 x 10-23
J/K
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